I'm gonna be really bored this weekend so I might aswell help some people. I'm doing University Calculus and Algebra so I should be able to solve most problems. If you have any problems for me to solve, feel free to post them below. I'll put my working with it for you to follow. I just love Maths :worm
There are n sweets in a bag. Six of the sweets are orange. The rest of the sweets are yellow. Hannah takes a sweet from the bag. She eats the sweet. Hannah then takes at random another sweet from the bag. She eats the sweet. The probability that Hannah eats two orange sweets is 1/3. Show that n²-n-90=0
n must be 10 since 10^2-10-90=0 10-6=4 4 yellow sweets so 2 orange sweets would be 4+2=6, 2/6=1/3 (I think this is right xD)
Gyazo - cbe68d32848e746dbc7d87a5bdd7cb86.png Gyazo - 6970eda2bd8d5ecab5e104ceed62017e.png Have fun bb
6/n = the probability of taking the first sweet 5/(n-1) = the probability of taking the second sweet These two multiplied by each other gives us the probability of being chosen in a row (6/n)(5/(n-1)) = 30/(n^2-n) It tells us that this probability is 1/3 so we set our formed expression to equal to 1/3 30/(n^2-n)=1/3 We then simplify it to get 90=n^2-n Set this equal to 0 and we get: n^2 -n -90=0 That's all the question asks from you. You don't need to solve for n.