Helping People with their maths homework :D

Discussion in 'Off-Topic' started by PhilsNZ, Sep 18, 2015.

  1. PhilsNZ
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    PhilsNZ Well-Known Member

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    First Link:
    1)
    2*6' + 2 feet = 3 feet (12 inches = 1 foot)
    2)
    3x-1 = -5x +15
    Bring all x values to one side
    8x = 16
    x=2
    3)
    I cant read what it says
    4)
    -x -4(5x -21)=-21 Substitute equation 2 into the y value of equation 1
    -x -20x +84 = -21
    -21x = -105 Divide both sides by (-21)
    x = 5
    5)
    Equation 1 - 2*Equation 2
    6x-2(3x) -9y-2(18y)=-3 -2(21)
    0 -45y = -45
    y = 1
    Substituting y into either of the equations will give us x
    3x +18(1) = 21
    3x = 3
    x = 1, y = 1
    6)
    Find common factor between 5 and 8, its easiest to multiply them by each other to get this.
    8*(5x + 2y = 5)
    5*(8x + 3y = 6)

    40x + 16y = 40
    40x + 15y = 30 Subtract them from each other.

    40x-40x +16y-15y = 40-30
    y = 10
    7)
    y = (3/2)x + 4
    (3/2)x determines the slope (2 out, 3 up) and the +4 determines the y-intercept.
    Equation of a line is y = mx+c where m is the gradient and c the y intercept.
    [​IMG]
    8)
    Set equal to y first.
    y = (3/5)x - 10
    It will have a gradient of 3/5 and its y-intercept will be 10 units below the origin.
    [​IMG]
    9)
    The key term in here is "compounded Monthly"
    Therefore Final amount = Initial amount * (1+ the monthly % rate in decimal) ^ months*years.
    F = 1000(1+0.028)^(10*12)
    F= 1000(1.028)^120
    F= 27489.94 (2 D.P)
    This value is so huge because usually, compound interest is added annually, not monthly.
    10)
    6x - 5y = 15 Set this = y
    5y = 6x-15
    y = (6/5)x -3
    y = mx + c where m is the gradient/slope
    slope = m = 6/5

    If I made a mistake somewhere, please tell me ^^
     
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  2. PhilsNZ
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    PhilsNZ Well-Known Member

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    ill do the second link in like an hour
     
  3. DarthBread
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    DarthBread Experienced Member

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    LOL wasnt expecting the graphs but ok thanks bb :heart:
     
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  4. DarthBread
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    DarthBread Experienced Member

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    The class is, idk about the homework. Barely looked at it lol
     
  5. PhilsNZ
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    PhilsNZ Well-Known Member

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    But that's not what the question wants from you :p
     
  6. HoggyTehBeqr
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    HoggyTehBeqr Active Member

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    Do my trig hw. Jk jk
     
  7. PhilsNZ
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    PhilsNZ Well-Known Member

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    Oooh i like trig :D
     
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  8. GTechNerd
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    GTechNerd Well-Known Member

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    I love everything except for probability.
     
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  9. HoggyTehBeqr
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    HoggyTehBeqr Active Member

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    OMG, I hate probability.
     
  10. PhilsNZ
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    PhilsNZ Well-Known Member

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    If you need help, just post it in here :)
     
  11. PhilsNZ
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    PhilsNZ Well-Known Member

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    Allrighty, heres the answers to the second link.
    11) The constant would be 0, however i'm actually not too sure with this one.
    12) Given f(x)= 2-x, find f(2). Just substitute 2 into the x. Therefore f(2)=0
    13)x = 6 does not have a y intercept as x = 3 is not a function but just a variable. It will graph a vertical line at x=6
    14) y= x^2 + 1 is definitely not linear. As soon as you see that it is a polynomial, you know that it isnt.
    15) It will just be a vertical line at x = 3
    16) Note that you could zoom in indefinitely on the dotted lines and it would never actually touch them.
    [​IMG]
    17)
    [​IMG]
    18) If 2x-1 = 2(x-1) then when simplified you should end up with 0=0. However this is not the case with this problem. (Note: ≠ means "not equal to")
    2x - 1 2x -2
    -1 -2
    0 -1
    We know that 0 is not the same as -1 therefore this has proven our point.
    19)
    [​IMG]
    20) I've never done Linear inequalities with graphing so I'm not entirely sure with this.
    (-5, -5) would be a solution to number 19, because that is part of the area where the 2 inequalities overlap. Therefore it would be a solution to both inequalities. Any value in that overlapping triangle would be a possible solution. And as these values could be infinitesimally small, there would be an infinite set of solutions.
     
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  12. GTechNerd
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    GTechNerd Well-Known Member

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    The coordinates fall on the dotted lines, so I'm not sure about it being a solution to the inequalities. DarthBread, check your notes regarding coordinates falling on dotted lines.
     
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  13. PhilsNZ
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    PhilsNZ Well-Known Member

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    Yes, you're right Gtech, I went over it, it cannot be a solution. :) Thank you ^^
    -5 > -5 is wrong so that pretty much is the proof.
     
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  14. GTechNerd
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    GTechNerd Well-Known Member

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    There we go. I think it is only a solution if the coordinates fall on a solid line. That way works too, now that you told me.
     
  15. PhilsNZ
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    PhilsNZ Well-Known Member

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    I'm certain it can be any value within the overlap. Test it, take out 2 values and put them in xD
     
  16. DarthBread
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    DarthBread Experienced Member

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    I'm just gonna give you my homework all year lmfao
     
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  17. GTechNerd
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    GTechNerd Well-Known Member

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    This is gonna be you:

    upload_2015-9-19_11-27-43.png
     
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  18. DarthBread
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    DarthBread Experienced Member

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  19. ISuika
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    ISuika Senior Member

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    I nailed the s*** out of that question in the exam
     
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  20. SomeoneCalledJ
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    SomeoneCalledJ Experienced Member

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    Gonna start using this for now on, whenever I receive homework. lmao
     

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